Using Ohm's Law, what is the current if resistance is 5 Ohms and voltage is 25V?

Using Ohm's Law, what is the current if resistance is 5 Ohms and voltage is 25V?

• A. 5A
• B. 15A
• C. 3A
• D. 25A

Answer: (A)

To determine the current using Ohm's Law, the formula applied is: \[ I = \frac{V}{R} \] where: - \( I \) is the current in amperes (A), - \( V \) is the voltage in volts (V), - \( R \) is the resistance in ohms (Ω). In this scenario, the voltage (\( V \)) is 25 volts, and the resistance (\( R \)) is 5 ohms. When substituting these values into the formula, you have: \[ I = \frac{25V}{5Ω} = 5A \] Thus, the current is 5 amperes. This aligns with one of the choices given in the question, confirming that the reasoning and calculation using Ohm's Law correctly determine the current flowing through the circuit. Understanding this relationship between voltage, current, and resistance is fundamental in electrical engineering and is a critical concept for topics covered in the NACE CP1 exam.

To determine the current using Ohm's Law, the formula applied is:

[ I = \frac{V}{R} ]

where:

• ( I ) is the current in amperes (A),

• ( V ) is the voltage in volts (V),

• ( R ) is the resistance in ohms (Ω).

In this scenario, the voltage (( V )) is 25 volts, and the resistance (( R )) is 5 ohms. When substituting these values into the formula, you have:

[ I = \frac{25V}{5Ω} = 5A ]

Thus, the current is 5 amperes. This aligns with one of the choices given in the question, confirming that the reasoning and calculation using Ohm's Law correctly determine the current flowing through the circuit. Understanding this relationship between voltage, current, and resistance is fundamental in electrical engineering and is a critical concept for topics covered in the NACE CP1 exam.